TCS Digital Placement Papers 2026 | Questions, Exam Pattern & Prep

Last Updated: June 2026

Sourcing note

Selection process details, round structure, and difficulty observations on this page are based on public preparation resources, candidate-reported accounts on platforms including Glassdoor, Blind, and the TCS NQT community forums, and the official TCS careers portal (tcs.com/careers). Compensation figures and band cut-offs are candidate-reported and indicative. Confirm the current package and eligibility on the official TCS NQT portal before applying.

Truth check — what actually matters for TCS 2026

TCS is the volume play, not the prestige play, and that is the entire framing. NQT (National Qualifier Test) is the front door for almost every fresher route, Ninja, Digital, Prime, and the band you land in is decided more by the test than the interview. The interview is largely a pass/fail filter, not a tier decider.

Candidates report that TCS hires a very large volume of freshers each year via NQT cycles. What matters most is band allocation, which is decided by test performance. Experienced lateral demand stays steady, and that is the band most candidates eventually move into post-band-promotion around 18 months in.

What guides keep getting wrong: you do not need to "crack" NQT. You need to maximize foundation + verbal. Verbal is where most engineering candidates underperform, and verbal sections are the cheapest to drill in under 50 hours of focused practice. The programming logic round is multiple-choice, covering output prediction, error prediction, and complexity analysis. Practice format, not raw algorithms.

If you are aiming for Digital or Prime, the differentiator is the additional advanced coding round (candidate reports indicate approximately 60-90 minutes of hard DSA). That is where prep diverges from Ninja-only candidates. Without DSA preparation at LeetCode-medium level, you will not clear Digital, and the band offer difference compounds across appraisal cycles.

If you have 2 weeks for TCS NQT only: Foundation (verbal + numerical + reasoning) for 9 days at the format-drill level, programming-logic-MCQ for 3 days, mock interview for 2. Skip aggressive DSA unless you are targeting Digital/Prime.

TCS Digital is the premium hiring track at Tata Consultancy Services, offering a significantly higher package of ₹7-7.3 LPA compared to the standard Ninja profile. This track is designed for candidates with strong technical skills and problem-solving abilities.

TCS Digital Program Overview

Eligibility Criteria

• Academic: Minimum 70% or 7 CGPA throughout (10th, 12th, Graduation)
• Backlogs: No active backlogs
• Gap: Maximum 1 year gap between academics
• Degree: Full-time courses from recognized universities
• Additional: Strong programming and problem-solving skills required

TCS Digital vs Ninja Comparison

TCS Digital Exam Pattern

15 Sample Questions with Solutions

Advanced Aptitude (Questions 1-4)

Q1. If log₂(log₃(log₄x)) = 0, what is the value of x?

• a) 64
• b) 81
• c) 256
• d) 4

Solution: log₂(log₃(log₄x)) = 0 → log₃(log₄x) = 2⁰ = 1 → log₄x = 3¹ = 3 → x = 4³ = 64

Q2. A and B can complete a work in 12 days. B and C in 15 days. C and A in 20 days. How long will A alone take?

• a) 20 days
• b) 25 days
• c) 30 days
• d) 35 days

Solution: 2(A+B+C) = 1/12 + 1/15 + 1/20 = (5+4+3)/60 = 12/60 = 1/5. So A+B+C = 1/10. A = (A+B+C) - (B+C) = 1/10 - 1/15 = 1/30. Days = 30.

Q3. The sum of the first n odd natural numbers is:

• a) n(n+1)
• b) n²
• c) 2n²
• d) n(n+1)/2

Explanation: 1 + 3 + 5 + ... + (2n-1) = n²

Q4. A man rows upstream at 8 km/hr and downstream at 12 km/hr. What is the speed of the stream?

• a) 2 km/hr
• b) 4 km/hr
• c) 6 km/hr
• d) 8 km/hr

Solution: Speed of stream = (Downstream - Upstream)/2 = (12-8)/2 = 2 km/hr

Advanced Logical Reasoning (Questions 5-7)

Q5. In a code language, '123' means 'bright little boy', '145' means 'tall big boy', and '637' means 'beautiful little flower'. Which digit represents 'bright'?

• a) 1
• b) 2
• c) 3
• d) 4

Solution: From 123 and 145: '1' = 'boy'. From 123 and 637: '3' = 'little'. So '2' = 'bright'.

Q6. Six friends A, B, C, D, E, and F are sitting in a circle facing the center. A is between D and F. C is between E and B. E is not next to D. Who is between A and C?

• a) B
• b) D
• c) E
• d) F

Explanation: Arrangement (clockwise): D-A-F-?-E-C-B. Since E is not next to D, the arrangement is D-A-F-B-E-C. So D is between C and A (going the other way).

Q7. Complete the pattern: 1, 2, 6, 24, 120, ?

• a) 600
• b) 720
• c) 840
• d) 5040

Solution: Pattern: ×2, ×3, ×4, ×5, ×6 → 120 × 6 = 720 (Factorials: 1!, 2!, 3!, 4!, 5!, 6!)

Programming Concepts (Questions 8-10)

Q8. What is the time complexity of the following code?

for(int i = 0; i < n; i++)
    for(int j = 0; j < i; j++)
        printf("*");

• a) O(n)
• b) O(n²)
• c) O(n log n)
• d) O(n³)

Explanation: Inner loop runs 0 + 1 + 2 + ... + (n-1) = n(n-1)/2 = O(n²)

Q9. Which data structure is best for implementing LRU (Least Recently Used) cache?

• a) Array
• b) Stack
• c) Queue
• d) Hash Map + Doubly Linked List

Q10. What is the output of the following Java code?

class Test {
    public static void main(String[] args) {
        String s1 = new String("Hello");
        String s2 = new String("Hello");
        System.out.println(s1 == s2);
        System.out.println(s1.equals(s2));
    }
}

• a) true true
• b) false true
• c) true false
• d) false false

Explanation: '==' compares references (different objects), equals() compares content.

Data Structures & Algorithms (Questions 11-12)

Q11. Which algorithm is most efficient for finding the shortest path in a weighted graph with negative edges?

• a) Dijkstra's
• b) Bellman-Ford
• c) Floyd-Warshall
• d) BFS

Explanation: Bellman-Ford handles negative edge weights, unlike Dijkstra's.

Q12. What is the best case time complexity of QuickSort?

• a) O(n)
• b) O(n log n)
• c) O(n²)
• d) O(log n)

Advanced Coding Questions (Questions 13-15)

Q13. Write a program to find the longest palindromic substring.

Solution:

def longest_palindrome(s):
    if not s:
        return ""
    
    start, max_len = 0, 1
    
    for i in range(len(s)):
        # Odd length palindromes
        l, r = i, i
        while l >= 0 and r < len(s) and s[l] == s[r]:
            if r - l + 1 > max_len:
                start = l
                max_len = r - l + 1
            l -= 1
            r += 1
        
        # Even length palindromes
        l, r = i, i + 1
        while l >= 0 and r < len(s) and s[l] == s[r]:
            if r - l + 1 > max_len:
                start = l
                max_len = r - l + 1
            l -= 1
            r += 1
    
    return s[start:start + max_len]

s = input()
print(longest_palindrome(s))

Q14. Write a program to find the maximum sum subarray (Kadane's Algorithm).

Solution:

#include<stdio.h>

int max_subarray_sum(int arr[], int n) {
    int max_so_far = arr[0];
    int max_ending_here = arr[0];
    
    for(int i = 1; i < n; i++) {
        if(max_ending_here + arr[i] > arr[i])
            max_ending_here = max_ending_here + arr[i];
        else
            max_ending_here = arr[i];
        
        if(max_ending_here > max_so_far)
            max_so_far = max_ending_here;
    }
    
    return max_so_far;
}

int main() {
    int n;
    scanf("%d", &n);
    int arr[n];
    for(int i = 0; i < n; i++)
        scanf("%d", &arr[i]);
    printf("%d", max_subarray_sum(arr, n));
    return 0;
}

Q15. Write a program to detect a cycle in a linked list.

Solution:

class Node {
    int data;
    Node next;
    Node(int d) { data = d; next = null; }
}

class LinkedList {
    Node head;
    
    boolean hasCycle() {
        Node slow = head, fast = head;
        while(fast != null && fast.next != null) {
            slow = slow.next;
            fast = fast.next.next;
            if(slow == fast)
                return true;
        }
        return false;
    }
}

Topic-Wise Weightage

Preparation Tips for TCS Digital

1. Advanced Aptitude

• Focus on advanced topics like logarithms, permutations, probability
• Practice complex DI problems
• Solve CAT-level quantitative questions
• Focus on speed and accuracy

2. Logical Reasoning

• Practice advanced puzzles
• Focus on data sufficiency
• Solve seating arrangement with multiple variables
• Practice coding-decoding variations

3. Programming Concepts

• Master data structures thoroughly
• Understand time and space complexity
• Study OOPs concepts in depth
• Learn DBMS and OS fundamentals

4. Advanced Coding

• Practice on LeetCode Medium-Hard problems
• Focus on: Arrays, Strings, Linked Lists, Trees, DP
• Learn standard algorithms
• Practice writing optimized code

Recommended Study Resources

2-Week TCS Digital Prep Plan

Plan based on candidate-reported preparation strategies from public forums. Adapt based on your current baseline.

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🎯 Live Mock Test, May 2026 Edition

5 original questions written by Aditya Sharma, calibrated to the Tcs Digital 2026 batch difficulty. Click any option to lock your answer; solutions reveal after.