TCS Digital Placement Papers 2026 — Questions & Preparation

Last Updated: March 2026

TCS Digital is the premium hiring track at Tata Consultancy Services, offering a significantly higher package of ₹7-7.3 LPA compared to the standard Ninja profile. This track is designed for candidates with strong technical skills and problem-solving abilities.

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TCS Digital Program Overview

Aspect	Details
Full Form	TCS Digital Hiring
Package	₹7.0 - 7.3 LPA
Role	Digital Technology Engineer
Training	Advanced technical training
Projects	Digital transformation projects
Eligibility	BE/B.Tech/ME/M.Tech/MCA/M.Sc (CS/IT) with 70%+

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Eligibility Criteria

• Academic: Minimum 70% or 7 CGPA throughout (10th, 12th, Graduation)
• Backlogs: No active backlogs
• Gap: Maximum 1 year gap between academics
• Degree: Full-time courses from recognized universities
• Additional: Strong programming and problem-solving skills required

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TCS Digital vs Ninja Comparison

Feature	TCS Digital	TCS Ninja
Package	₹7-7.3 LPA	₹3.36 LPA
Difficulty Level	High	Moderate
Coding Questions	3-4 (Advanced)	2 (Basic-Moderate)
Technical Interview	Advanced topics	Basic concepts
Cut-off	80%+	65-70%
Training	Advanced	Standard

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TCS Digital Exam Pattern

Section	Questions	Duration	Difficulty
Aptitude (Advanced)	20	40 min	Hard
Logical Reasoning	20	40 min	Hard
Verbal Ability	15	20 min	Moderate
Programming MCQs	10	15 min	Hard
Advanced Coding	3-4	60-90 min	Hard
Total	65-70	175-205 min	-

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15 Sample Questions with Solutions

Advanced Aptitude (Questions 1-4)

Q1. If log₂(log₃(log₄x)) = 0, what is the value of x?

• a) 64
• b) 81
• c) 256
• d) 4

Solution: log₂(log₃(log₄x)) = 0 → log₃(log₄x) = 2⁰ = 1 → log₄x = 3¹ = 3 → x = 4³ = 64

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Q2. A and B can complete a work in 12 days. B and C in 15 days. C and A in 20 days. How long will A alone take?

• a) 20 days
• b) 25 days
• c) 30 days
• d) 35 days

Solution: 2(A+B+C) = 1/12 + 1/15 + 1/20 = (5+4+3)/60 = 12/60 = 1/5. So A+B+C = 1/10. A = (A+B+C) - (B+C) = 1/10 - 1/15 = 1/30. Days = 30.

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Q3. The sum of the first n odd natural numbers is:

• a) n(n+1)
• b) n²
• c) 2n²
• d) n(n+1)/2

Explanation: 1 + 3 + 5 + ... + (2n-1) = n²

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Q4. A man rows upstream at 8 km/hr and downstream at 12 km/hr. What is the speed of the stream?

• a) 2 km/hr
• b) 4 km/hr
• c) 6 km/hr
• d) 8 km/hr

Solution: Speed of stream = (Downstream - Upstream)/2 = (12-8)/2 = 2 km/hr

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Advanced Logical Reasoning (Questions 5-7)

Q5. In a code language, '123' means 'bright little boy', '145' means 'tall big boy', and '637' means 'beautiful little flower'. Which digit represents 'bright'?

• a) 1
• b) 2
• c) 3
• d) 4

Solution: From 123 and 145: '1' = 'boy'. From 123 and 637: '3' = 'little'. So '2' = 'bright'.

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Q6. Six friends A, B, C, D, E, and F are sitting in a circle facing the center. A is between D and F. C is between E and B. E is not next to D. Who is between A and C?

• a) B
• b) D
• c) E
• d) F

Explanation: Arrangement (clockwise): D-A-F-?-E-C-B. Since E is not next to D, the arrangement is D-A-F-B-E-C. So D is between C and A (going the other way).

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Q7. Complete the pattern: 1, 2, 6, 24, 120, ?

• a) 600
• b) 720
• c) 840
• d) 5040

Solution: Pattern: ×2, ×3, ×4, ×5, ×6 → 120 × 6 = 720 (Factorials: 1!, 2!, 3!, 4!, 5!, 6!)

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Programming Concepts (Questions 8-10)

Q8. What is the time complexity of the following code?

for(int i = 0; i < n; i++)
    for(int j = 0; j < i; j++)
        printf("*");

• a) O(n)
• b) O(n²)
• c) O(n log n)
• d) O(n³)

Explanation: Inner loop runs 0 + 1 + 2 + ... + (n-1) = n(n-1)/2 = O(n²)

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Q9. Which data structure is best for implementing LRU (Least Recently Used) cache?

• a) Array
• b) Stack
• c) Queue
• d) Hash Map + Doubly Linked List

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Q10. What is the output of the following Java code?

class Test {
    public static void main(String[] args) {
        String s1 = new String("Hello");
        String s2 = new String("Hello");
        System.out.println(s1 == s2);
        System.out.println(s1.equals(s2));
    }
}

• a) true true
• b) false true
• c) true false
• d) false false

Explanation: '==' compares references (different objects), equals() compares content.

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Data Structures & Algorithms (Questions 11-12)

Q11. Which algorithm is most efficient for finding the shortest path in a weighted graph with negative edges?

• a) Dijkstra's
• b) Bellman-Ford
• c) Floyd-Warshall
• d) BFS

Explanation: Bellman-Ford handles negative edge weights, unlike Dijkstra's.

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Q12. What is the best case time complexity of QuickSort?

• a) O(n)
• b) O(n log n)
• c) O(n²)
• d) O(log n)

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Advanced Coding Questions (Questions 13-15)

Q13. Write a program to find the longest palindromic substring.

Solution:

def longest_palindrome(s):
    if not s:
        return ""
    
    start, max_len = 0, 1
    
    for i in range(len(s)):
        # Odd length palindromes
        l, r = i, i
        while l >= 0 and r < len(s) and s[l] == s[r]:
            if r - l + 1 > max_len:
                start = l
                max_len = r - l + 1
            l -= 1
            r += 1
        
        # Even length palindromes
        l, r = i, i + 1
        while l >= 0 and r < len(s) and s[l] == s[r]:
            if r - l + 1 > max_len:
                start = l
                max_len = r - l + 1
            l -= 1
            r += 1
    
    return s[start:start + max_len]

s = input()
print(longest_palindrome(s))

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Q14. Write a program to find the maximum sum subarray (Kadane's Algorithm).

Solution:

#include<stdio.h>

int max_subarray_sum(int arr[], int n) {
    int max_so_far = arr[0];
    int max_ending_here = arr[0];
    
    for(int i = 1; i < n; i++) {
        if(max_ending_here + arr[i] > arr[i])
            max_ending_here = max_ending_here + arr[i];
        else
            max_ending_here = arr[i];
        
        if(max_ending_here > max_so_far)
            max_so_far = max_ending_here;
    }
    
    return max_so_far;
}

int main() {
    int n;
    scanf("%d", &n);
    int arr[n];
    for(int i = 0; i < n; i++)
        scanf("%d", &arr[i]);
    printf("%d", max_subarray_sum(arr, n));
    return 0;
}

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Q15. Write a program to detect a cycle in a linked list.

Solution:

class Node {
    int data;
    Node next;
    Node(int d) { data = d; next = null; }
}

class LinkedList {
    Node head;
    
    boolean hasCycle() {
        Node slow = head, fast = head;
        while(fast != null && fast.next != null) {
            slow = slow.next;
            fast = fast.next.next;
            if(slow == fast)
                return true;
        }
        return false;
    }
}

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Topic-Wise Weightage

Section	Weightage	Priority
Advanced Aptitude	25%	High
Logical Reasoning	25%	High
Programming MCQs	15%	Medium
Advanced Coding	25%	Very High
Verbal Ability	10%	Low

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Preparation Tips for TCS Digital

1. Advanced Aptitude

• Focus on advanced topics like logarithms, permutations, probability
• Practice complex DI problems
• Solve CAT-level quantitative questions
• Focus on speed and accuracy

2. Logical Reasoning

• Practice advanced puzzles
• Focus on data sufficiency
• Solve seating arrangement with multiple variables
• Practice coding-decoding variations

3. Programming Concepts

• Master data structures thoroughly
• Understand time and space complexity
• Study OOPs concepts in depth
• Learn DBMS and OS fundamentals

4. Advanced Coding

• Practice on LeetCode Medium-Hard problems
• Focus on: Arrays, Strings, Linked Lists, Trees, DP
• Learn standard algorithms
• Practice writing optimized code

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Recommended Study Resources

Resource	Purpose
LeetCode	Coding practice (Medium-Hard)
GeeksforGeeks	Technical concepts
HackerRank	Problem solving
Indiabix	Aptitude practice

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Frequently Asked Questions (FAQs)

Q1. Can I directly apply for TCS Digital? A: Yes, if you meet the eligibility criteria (70%+ throughout).

Q2. What is the cut-off for TCS Digital? A: Usually 80-85% overall with good performance in coding sections.

Q3. Is TCS Digital tougher than Ninja? A: Yes, significantly tougher with advanced questions in all sections.

Q4. What coding topics should I focus on? A: Arrays, strings, linked lists, trees, dynamic programming, and graph algorithms.

Q5. Can I get TCS Digital if I applied for Ninja? A: Sometimes candidates who perform exceptionally well in Ninja are upgraded to Digital.

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Related Resources:

• TCS Exam Pattern 2026
• TCS Ninja Placement Papers 2026
• TCS Off Campus Drive 2026

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All the best for your TCS Digital preparation! 🚀