Races And Games Questions Placement
Races and Games Questions for Placement (with Solutions)
Last Updated: March 2026
Races and Games is an interesting topic in quantitative aptitude dealing with contests of speed, distance, and time between competitors. This guide provides 30 practice questions with detailed solutions.
Key Concepts and Formulas
Race Terminology
- Dead Heat: When contestants finish exactly together
- Start/Head Start: One contestant starts ahead of another
- Postponed Start: One contestant starts later
- Winning Distance: Distance by which winner beats opponent
Important Formulas
When A beats B by x meters in a y-meter race:
- While A runs y meters, B runs (y-x) meters
- Speed ratio A:B = y : (y-x)
When A beats B by t seconds:
- A's time = T, B's time = T + t
- Speed ratio = (T+t) : T
When A gives B a start of x meters:
- A runs y meters, B runs (y-x) meters
- Race is dead heat or A still wins
Games (Points System)
- Winner scores points based on difference in performance
- Game is won by player reaching target points first
30 Practice Questions with Solutions
Level 1: Basic (Questions 1-10)
Q1. In a 100 m race, A can give B 10 m and C 28 m. In the same race, B can give C:
Solution: When A runs 100m, B runs 90m, C runs 72m
So when B runs 90m, C runs 72m When B runs 100m, C runs (72/90) × 100 = 80m
B can give C = 100 - 80 = 20 m
Q2. In a 200 metres race A beats B by 35 m or 7 seconds. What is A's time over the course?
Solution: B runs 35 m in 7 seconds B's speed = 35/7 = 5 m/s
Time for B to run 200m = 200/5 = 40 seconds
A's time = 40 - 7 = 33 seconds
Q3. In a game of 100 points, A can give B 20 points and C 28 points. Then, B can give C:
Solution: When A scores 100, B scores 80, C scores 72
When B scores 80, C scores 72 When B scores 100, C scores (72/80) × 100 = 90
B can give C = 100 - 90 = 10 points
Q4. In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race, A can beat C by:
Solution: When A runs 100m, B runs 75m When B runs 100m, C runs 96m
So when B runs 75m, C runs (96/100) × 75 = 72m
When A runs 100m, C runs 72m A beats C by 100 - 72 = 28 m
Q5. In a 100 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by:
Solution: In 36 seconds, B covers (100/45) × 36 = 80m
A beats B by 100 - 80 = 20 m
Alternative: Distance = Speed × Time difference B's speed = 100/45 m/s Distance = (100/45) × (45-36) = (100/45) × 9 = 20m
Q6. In a 500 m race, the ratio of the speeds of two contestants A and B is 3:4. A has a start of 140 m. Then, A wins by:
Solution: A runs (500-140) = 360m while B runs 500m
Speed ratio A:B = 3:4 Distance ratio should be 3:4
For same time: 360/500 = 3/4.167 ≠ 3/4
Let's calculate properly: When A runs 360m, B runs (4/3) × 360 = 480m
So when A finishes 360m, B is at 480m A wins by 500 - 480 = 20 m
Q7. In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by:
Solution: When A runs 100m, B runs 90m, C runs 87m
When B runs 90m, C runs 87m When B runs 180m, C runs (87/90) × 180 = 174m
B beats C by 180 - 174 = 6 m
Q8. A and B take part in a 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. What is the speed of B?
Solution: A's speed = 5 kmph = 5000/3600 m/s = 25/18 m/s
Time for A to run 100m = 100 × 18/25 = 72 seconds
B runs (100-8) = 92m in 72 + 8 = 80 seconds
B's speed = 92/80 m/s = (92/80) × (18/5) kmph = 4.14 kmph
Actually: Speed = 92/80 × 18/5 = 1035/125 = 4.14 kmph or exactly 207/50 kmph
Let's simplify: 92/80 = 23/20 Speed = 23/20 × 18/5 = 414/100 = 4.14 kmph
Q9. In a game of 90 points, A can give B 15 points and C 30 points. Then, B can give C:
Solution: When A scores 90, B scores 75, C scores 60
When B scores 75, C scores 60 When B scores 90, C scores (60/75) × 90 = 72
B can give C = 90 - 72 = 18 points
Q10. A can run 22.5 m while B runs 25 m. In a kilometre race B beats A by:
Solution: When B runs 25m, A runs 22.5m When B runs 1000m, A runs (22.5/25) × 1000 = 900m
B beats A by 1000 - 900 = 100 m
Level 2: Moderate (Questions 11-20)
Q11. In a 200 m race, A beats B by 31 m and C by 18 m. In a race of 350 m, C will beat B by:
Solution: When A runs 200m, B runs 169m, C runs 182m
When C runs 182m, B runs 169m When C runs 350m, B runs (169/182) × 350 = 325m
C beats B by 350 - 325 = 25 m
Q12. In a race of 600 m, A can beat B by 60 m and in a race of 500 m, B can beat C by 50 m. By how many meters will A beat C in a race of 400 m?
Solution: When A runs 600m, B runs 540m When B runs 500m, C runs 450m
First find relationship between A and C: When B runs 540m, C runs (450/500) × 540 = 486m
So when A runs 600m, C runs 486m When A runs 400m, C runs (486/600) × 400 = 324m
A beats C by 400 - 324 = 76 m
Q13. In a kilometre race, A beats B by 100 m and B beats C by 100 m. By how many meters does A beat C in the same race?
Solution: When A runs 1000m, B runs 900m When B runs 1000m, C runs 900m
When B runs 900m, C runs (900/1000) × 900 = 810m
When A runs 1000m, C runs 810m A beats C by 1000 - 810 = 190 m
Q14. A runs 1⅔ times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time?
Solution: Speed ratio A:B = 5/3 : 1 = 5:3
For same time, distance ratio = 5:3
Let winning post be at x meters from A's start A runs x meters, B runs (x-80) meters
x/(x-80) = 5/3 3x = 5x - 400 2x = 400 x = 200
Q15. A and B run a kilometer race and A wins by 1 minute. A and C run a kilometre race and A wins by 375 m. B and C run a kilometre race and B wins by 30 seconds. Find the time taken by B to run 1000 m.
Solution: Let speeds be a, b, c m/s
From A vs B: 1000/b - 1000/a = 60 ... (1) From A vs C: When A runs 1000, C runs 625 So 1000/a = 625/c, thus c = 5a/8
From B vs C: 1000/c - 1000/b = 30 1000/(5a/8) - 1000/b = 30 1600/a - 1000/b = 30 ... (2)
From (1): 1000/b = 1000/a + 60 Substitute in (2): 1600/a - (1000/a + 60) = 30 600/a = 90 a = 600/90 = 20/3 m/s
Time for A = 1000 × 3/20 = 150 seconds Time for B = 150 + 60 = 210 seconds = 3.5 minutes
Q16. In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by:
Solution: Same as Q7
B beats C by 6 m
Q17. A and B can cover a 200 m race in 22 seconds and 25 seconds respectively. When A finishes the race, how far is B from the finishing line?
Solution: In 22 seconds, B covers (200/25) × 22 = 176m
B is 200 - 176 = 24 m from finish
Q18. In a game of billiards, A can give B 20 points in 60 and he can give C 30 points in 60. How many points can B give C in a game of 100?
Solution: When A scores 60, B scores 40, C scores 30
When B scores 40, C scores 30 When B scores 100, C scores (30/40) × 100 = 75
B can give C = 100 - 75 = 25 points
Q19. In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race, A can beat C by:
Solution: Same as Q4
A beats C by 28 m
Q20. In a kilometre race, A beats B by 30 seconds and B beats C by 15 seconds. If A beats C by 180 m, what is the time taken by A to run the kilometre?
Solution: A beats C by 30 + 15 = 45 seconds
In 45 seconds, C runs 180 m C's speed = 180/45 = 4 m/s
Time for C to run 1000m = 1000/4 = 250 seconds Time for A = 250 - 45 = 205 seconds
Level 3: Advanced (Questions 21-30)
Q21. In a race of 1000 m, A can beat B by 100 m. In a race of 800 m, B can beat C by 100 m. By how many meters will A beat C in a race of 600 m?
Solution: When A runs 1000m, B runs 900m When B runs 800m, C runs 700m
When B runs 900m, C runs (700/800) × 900 = 787.5m
When A runs 1000m, C runs 787.5m When A runs 600m, C runs (787.5/1000) × 600 = 472.5m
A beats C by 600 - 472.5 = 127.5 m
Q22. In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by:
Solution: Same as Q7 and Q16
B beats C by 6 m
Q23. A and B take part in a 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. What is the speed of B?
Solution: Same as Q8
B's speed = 4.14 kmph or 207/50 kmph
Q24. In a game of 90 points, A can give B 15 points and C 30 points. Then, B can give C:
Solution: Same as Q9
B can give C 18 points
Q25. In a 100 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by:
Solution: Same as Q5
A beats B by 20 m
Q26. A runs 1⅔ times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time?
Solution: Same as Q14
Winning post at 200 m
Q27. In a 200 m race, A beats B by 31 m and C by 18 m. In a race of 350 m, C will beat B by:
Solution: Same as Q11
C beats B by 25 m
Q28. In a race of 600 m, A can beat B by 60 m and in a race of 500 m, B can beat C by 50 m. By how many meters will A beat C in a race of 400 m?
Solution: Same as Q12
A beats C by 76 m
Q29. A can run 22.5 m while B runs 25 m. In a kilometre race B beats A by:
Solution: Same as Q10
B beats A by 100 m
Q30. In a kilometre race, A beats B by 100 m and B beats C by 100 m. By how many meters does A beat C in the same race?
Solution: Same as Q13
A beats C by 190 m
Shortcuts and Tricks
Trick 1: Chain Rule for Multiple Competitors
When A beats B and B beats C, combine ratios:
- If A:B = 100:90 and B:C = 100:80
- Then A:C = 100 × 100 : 90 × 80 = 100:72 (after normalizing)
Trick 2: Time-Distance Conversion
When time difference given, convert to distance using speed of slower runner.
Trick 3: Start Problems
For head start problems, set up equation: Distance_A / Speed_A = Distance_B / Speed_B
Trick 4: Game Points
Treat points like distance. When A scores x, B scores (x - given points).
Trick 5: Verify with Dead Heat
If contestants finish together, their effective speeds adjusted for start must be equal.
Companies Testing This Topic
| Company | Frequency | Difficulty |
|---|---|---|
| TCS | Sometimes | Easy-Medium |
| Infosys | Sometimes | Easy |
| Wipro | Rare | Medium |
| Cognizant | Sometimes | Easy |
| Accenture | Rare | Medium |
| Capgemini | Sometimes | Easy |
Frequently Asked Questions (FAQ)
Q1: Are races and games questions common in placements?
A: They're less common than other topics, appearing in about 30-40% of papers, usually 1 question. However, when they appear, they're often easy scoring opportunities.
Q2: What's the difference between "gives a start" and "beats by"?
A: "Gives a start of x meters" means one runner starts x meters ahead of the starting line. "Beats by x meters" means the winner finishes while the loser still has x meters to run.
Q3: How do I handle three-person race problems?
A: Use chain rule. Find relationship between A and B, then B and C, combine to get A and C. Always normalize to common race distance.
Q4: Can there be decimal answers in races and games?
A: Yes, especially in advanced problems. Don't round prematurely - keep fractions until final answer.
Q5: What are games in this context?
A: Games refer to point-based competitions (like billiards, card games) where players score points. The math is identical to races - just treat points as distance.
Master the ratio concept and Races and Games becomes easy!
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