Doordash Placement Papers 2026
DoorDash Placement Papers 2026 with Solutions
Meta Description: Prepare for DoorDash 2026 campus drive with latest placement papers, exam pattern analysis, and 20+ solved questions. Get ready to crack the food delivery and logistics leader's hiring process.
DoorDash is a technology company that connects consumers with their favorite local and national businesses in over 7,000 cities across the United States, Canada, Australia, Japan, and Germany. Founded in 2013 by Tony Xu, Stanley Tang, Andy Fang, and Evan Moore, DoorDash has become the leading food delivery platform in the United States, expanding beyond food to include grocery, retail, and convenience store delivery. With a mission to empower local economies, DoorDash builds products and services that help merchants grow, dashers earn, and consumers get what they need.
DoorDash's engineering culture emphasizes operational excellence, data-driven decision making, and solving complex logistics problems at scale. If you're targeting DoorDash placements in 2026, this comprehensive guide with real placement paper questions and detailed solutions is your ultimate preparation resource.
DoorDash Hiring Pattern 2026
Eligibility Criteria
| Parameter | Requirements |
|---|---|
| Degree | B.E./B.Tech/M.E./M.Tech/MCA/M.Sc (CS/IT) |
| Academic Requirement | Strong CS fundamentals; distributed systems knowledge is a plus |
| Backlogs | No active backlogs |
| Gap Criteria | Flexible, evaluated case-by-case |
| Package | ₹20-40 LPA (India) / $130K-200K (US) |
Selection Process Overview
- Online Assessment (90 minutes)
- Technical Phone Screen (45-60 minutes)
- Virtual Onsite - Coding Round (60 minutes)
- Virtual Onsite - System Design (60 minutes)
- Virtual Onsite - Behavioral (45 minutes)
DoorDash Online Assessment Pattern 2026
| Section | Number of Questions | Time | Difficulty |
|---|---|---|---|
| Aptitude & Problem Solving | 15 | 25 minutes | Medium |
| Technical MCQs | 10 | 15 minutes | Medium-High |
| Coding Problems | 2-3 | 50 minutes | High |
| Total | 27-28 | ~90 mins | - |
Note: DoorDash emphasizes algorithms, data structures, and system design for real-time logistics.
DoorDash Placement Papers 2026 - Practice Questions
Section 1: Quantitative Aptitude
Interactive Mock Test
Test your knowledge with 15 real placement questions. Get instant feedback and detailed solutions.
Section 2: Logical Reasoning
Section 3: Technical MCQs
Section 4: Coding Problems
Question 16
Problem: Implement a delivery route optimization algorithm that finds the shortest path to deliver multiple orders.
Solution:
import heapq
from typing import List, Tuple, Dict
class DeliveryRouteOptimizer:
def __init__(self):
self.graph = {} # location -> list of (neighbor, distance)
def add_location(self, location: str):
"""Add a delivery location"""
if location not in self.graph:
self.graph[location] = []
def add_road(self, location1: str, location2: str, distance: float):
"""Add a road between two locations"""
if location1 not in self.graph:
self.add_location(location1)
if location2 not in self.graph:
self.add_location(location2)
self.graph[location1].append((location2, distance))
self.graph[location2].append((location1, distance))
def shortest_path(self, start: str, end: str) -> Tuple[List[str], float]:
"""Find shortest path using Dijkstra's algorithm"""
if start not in self.graph or end not in self.graph:
return [], float('inf')
# Priority queue: (distance, current_location, path)
pq = [(0, start, [start])]
visited = set()
while pq:
current_dist, current_loc, path = heapq.heappop(pq)
if current_loc in visited:
continue
visited.add(current_loc)
# Check if we reached destination
if current_loc == end:
return path, current_dist
# Explore neighbors
for neighbor, edge_dist in self.graph[current_loc]:
if neighbor not in visited:
new_dist = current_dist + edge_dist
new_path = path + [neighbor]
heapq.heappush(pq, (new_dist, neighbor, new_path))
return [], float('inf')
def optimize_delivery_route(self, start: str, deliveries: List[str]) -> List[str]:
"""
Optimize delivery route for multiple deliveries (Traveling Salesman Problem approximation)
Uses nearest neighbor heuristic
"""
if not deliveries:
return [start]
current = start
unvisited = set(deliveries)
route = [start]
total_distance = 0
while unvisited:
# Find nearest unvisited delivery
nearest = None
min_dist = float('inf')
for delivery in unvisited:
path, dist = self.shortest_path(current, delivery)
if dist < min_dist:
min_dist = dist
nearest = delivery
if nearest is None:
break
# Add to route
route.append(nearest)
total_distance += min_dist
current = nearest
unvisited.remove(nearest)
# Return to start
path_back, dist_back = self.shortest_path(current, start)
total_distance += dist_back
return route, total_distance
def multiple_dasher_routing(self, dashers: List[str], deliveries: List[str]) -> Dict[str, List[str]]:
"""
Assign deliveries to multiple dashers optimally
Simple greedy assignment
"""
# Sort deliveries by distance from each dasher's starting point
assignments = {dasher: [] for dasher in dashers}
for delivery in deliveries:
# Find dasher closest to this delivery
best_dasher = None
best_distance = float('inf')
for dasher in dashers:
path, distance = self.shortest_path(dasher, delivery)
if distance < best_distance:
best_distance = distance
best_dasher = dasher
if best_dasher:
assignments[best_dasher].append(delivery)
return assignments
# Test
optimizer = DeliveryRouteOptimizer()
# Add locations and roads
locations = ["Restaurant", "Customer1", "Customer2", "Customer3", "Customer4"]
for loc in locations:
optimizer.add_location(loc)
# Add roads with distances
optimizer.add_road("Restaurant", "Customer1", 2.5)
optimizer.add_road("Restaurant", "Customer2", 3.0)
optimizer.add_road("Customer1", "Customer2", 1.5)
optimizer.add_road("Customer2", "Customer3", 2.0)
optimizer.add_road("Customer3", "Customer4", 1.0)
optimizer.add_road("Customer1", "Customer4", 2.5)
# Test shortest path
path, distance = optimizer.shortest_path("Restaurant", "Customer4")
print(f"Shortest path: {path}, Distance: {distance}")
# Test delivery route optimization
deliveries = ["Customer1", "Customer2", "Customer3", "Customer4"]
route, total_dist = optimizer.optimize_delivery_route("Restaurant", deliveries)
print(f"Optimized route: {route}, Total distance: {total_dist}")
# Test multiple dasher routing
dashers = ["Dasher1", "Dasher2"]
assignments = optimizer.multiple_dasher_routing(dashers, deliveries)
print(f"Dasher assignments: {assignments}")
Time Complexity: O(V²) for nearest neighbor TSP approximation
Space Complexity: O(V + E) for graph storage
Question 17
Problem: Design a real-time order tracking system for DoorDash.
Solution:
from datetime import datetime
from enum import Enum
from typing import Dict, List, Optional
import asyncio
class OrderStatus(Enum):
PLACED = "placed"
CONFIRMED = "confirmed"
PREPARING = "preparing"
READY = "ready"
PICKED_UP = "picked_up"
ON_THE_WAY = "on_the_way"
DELIVERED = "delivered"
CANCELLED = "cancelled"
class OrderEvent:
def __init__(self, order_id: str, status: OrderStatus, timestamp=None, location=None, dasher_id=None):
self.order_id = order_id
self.status = status
self.timestamp = timestamp or datetime.now()
self.location = location # Optional: GPS coordinates
self.dasher_id = dasher_id # Optional: Dasher assigned
def to_dict(self):
return {
"order_id": self.order_id,
"status": self.status.value,
"timestamp": self.timestamp.isoformat(),
"location": self.location,
"dasher_id": self.dasher_id
}
class OrderTracker:
def __init__(self):
self.orders = {} # order_id -> list of OrderEvent
self.subscribers = {} # order_id -> list of callback functions
self.status_handlers = {} # status -> handler function
def place_order(self, order_id: str, customer_id: str, restaurant_id: str, items: List[str]):
"""Place a new order"""
if order_id in self.orders:
raise ValueError(f"Order {order_id} already exists")
initial_event = OrderEvent(order_id, OrderStatus.PLACED)
self.orders[order_id] = {
"customer_id": customer_id,
"restaurant_id": restaurant_id,
"items": items,
"events": [initial_event],
"current_status": OrderStatus.PLACED,
"created_at": datetime.now()
}
self._notify_subscribers(order_id, initial_event)
return order_id
def update_status(self, order_id: str, status: OrderStatus, **kwargs):
"""Update order status"""
if order_id not in self.orders:
raise ValueError(f"Order {order_id} not found")
order = self.orders[order_id]
# Validate status transition
if not self._is_valid_transition(order["current_status"], status):
raise ValueError(f"Invalid status transition: {order['current_status']} -> {status}")
# Create event
event = OrderEvent(order_id, status, **kwargs)
order["events"].append(event)
order["current_status"] = status
# Call status handler if exists
if status in self.status_handlers:
self.status_handlers[status](order_id, order)
# Notify subscribers
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